Question
0 and 4

Answer

Let $\alpha=0$ and $\beta=4$
$\therefore \alpha+\beta=0+4=4 \text { and } \alpha \beta=0 \times 4=0$
$\therefore$ and quadratic equation is, $x^2-(\alpha+\beta) x+\alpha \beta=0$
$\therefore x ^2-(4) x +(0)=0 $
$\therefore x ^2-4 x =0$

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