0.10M CH3COOH is 1.34% ionised, calculate its Ka: - Vidyadip

MCQ

0.10M CH₃COOH is 1.34% ionised, calculate its K_a:

A
1.8 × 10^-5
B
1.8 × 10^-4
C
5 × 10^-4
D
4 × 10^-5

✓

Answer

1.8 × 10^-5

Explanation:

$\text{K}_{\text{a}}=\text{C}\alpha^2=0.1\times\frac{1.34}{100}\times\frac{1.34}{100}=1.795\times10^{-5}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Equilibrium→Equilibrium — all question types→Chemistry STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

Oxidation numbers of $P$ in $PO_4^{3-} , S$ in $SO_4^{2-}$ and that of $Cr$ in $Cr_2O_7^{2-}$ are respectively

Arrange the following carbanions in order of their decreasing stability.

$ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{H}\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\\text{CH}_3-\text{C}-\text{CH}_2\text{Br}\\\ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{CH}_3$
$\text{CH}_3-\text{CH}_2-\text{Br}$
$\text{CH}_3-\text{CH}_2-\text{C}{\text{H}}_2-\text{Br}$

When benzene is treated with excess of $C{l_2}$ in the presence of ${I_2}$, the end product is

The work done to contract a gas in a cylinder, is $ 462\, joules$. $128 \,joule$ energy is evolved in the process. What will be the internal energy change in the process.....$joules$

In the equilibrium $ HClO‌‌_4+H‌‌_2O $ $\rightleftharpoons$ $ H_2O^+$+$ClO_4^ - $

Arrange the carbanions, ${\left( {C{H_3}} \right)_3}\bar C,\,\bar CC{l_3},\,{\left( {C{H_3}} \right)_2}\bar CH,\,{C_6}{H_5}\bar C{H_2}$ in order of their decreasing stability

The correct order of catenation is

Which of the following process requires largest amount of energy?

The $IUPAC$ name of $C{H_3}C \equiv N$ is

The element which exists in liquid state for a wide range of temperature and can be used for measuring high temperature is :-