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JEE Main 3-April-2025 Paper - Shift 1 — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEEJEE Main 3-April-2025 Paper - Shift 14 Marks
Question
0.5 g of an organic compound on combustion gave 1.46 g of $CO _2$ and 0.9 g of $H _2 O$. The percentage of carbon in the compound is __________. (Nearest integer)
[Given : Molar mass (in $g mol ^{-1}$ ) $C : 12, H : 1$, O : 16]
✓

Answer

(80)
Organic $\rightarrow CO _2$
Compound
Applying POAC on 'C'
(mole) of 'C' in compound $= n _{ CO _2} \times 1$
So mass of 'C' in compound
$
=\frac{1.46}{44} \times 12
$
So, $\%$ of 'C' in compound $=\frac{1.46}{44} \times \frac{12}{0.5} \times 100$ $
= 79.63
$

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