MCQ
$0.5\, M$ ammonium benzoate is hydrolysed to $0.25$ percent, hence its hydrolysis constant is
- A$2.5 \times {10^{ - 5}}$
- B$1.5 \times {10^{ - 4}}$
- ✓$3.125 \times {10^{ - 6}}$
- D$6.25 \times {10^{ - 4}}$
$0.5 - \frac{{.25}}{{100}}$ $\frac{{.25}}{{100}}$ $\frac{{.25}}{{100}}$
According to Ostwald dilution law.
$K = \frac{{{\alpha ^2}C}}{{1 - \alpha }}$ $\left( {\therefore \;\;\alpha = \frac{{.25}}{{100}}} \right)$
$K = {\alpha ^2}C$ $\left( {\;\;1 - \alpha = {\rm{Very small}}} \right)$
$K = \frac{{.25}}{{100}} \times \frac{{.25}}{{100}} \times .5$ ; $K = 3.125 \times {10^{ - 6}}$
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