Question
$0.6\text{x}+\frac45=0.28\text{x}+1.16$
✓
Answer
$0.6\text{x} + \frac45 = 0.28\text{x} + 1.16$
Transposing $0.28x$ to $L.H.S$. and $45$ to $R.H.S$., we get
$ = 0.6x - 0.28x = 1.16 - 45 = 0.32x = 1.16 - 0.8 = 0.32x = 0.36$
Dividing both sides by $0.32,$ we get
$ = 0.32 \times 0.32 = 0.360.32 = x = 98$
Verification: Substituting $x = 98$ on both sides, we get
$0.6\Big(\frac98\Big) + 45 = 0.28\Big(\frac98\Big) + 1.16$
$\frac{5.4}{8} + \frac45 = \frac{2.52}8 + 1.16$
$0.675 + 0.8 = 0.315 + 1.16$
$1.475 = 1.475$
$L.H.S. = R.H.S$.
Hence, verified.
Transposing $0.28x$ to $L.H.S$. and $45$ to $R.H.S$., we get
$ = 0.6x - 0.28x = 1.16 - 45 = 0.32x = 1.16 - 0.8 = 0.32x = 0.36$
Dividing both sides by $0.32,$ we get
$ = 0.32 \times 0.32 = 0.360.32 = x = 98$
Verification: Substituting $x = 98$ on both sides, we get
$0.6\Big(\frac98\Big) + 45 = 0.28\Big(\frac98\Big) + 1.16$
$\frac{5.4}{8} + \frac45 = \frac{2.52}8 + 1.16$
$0.675 + 0.8 = 0.315 + 1.16$
$1.475 = 1.475$
$L.H.S. = R.H.S$.
Hence, verified.
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