MCQ
$1-2 \sin ^2\left(\frac{\pi}{4}+\theta\right)=$
  • A
    $\cos 2 \theta$
  • B
    $-\cos 2 \theta$
  • C
    $\sin 2 \theta$
  • $-\sin 2 \theta$

Answer

Correct option: D.
$-\sin 2 \theta$
(D)
$1-2 \sin ^2\left(\frac{\pi}{4}+\theta\right)-\cos \left(\frac{\pi}{2}+2 \theta\right)$
$\ldots\left[\because \cos 2 \theta=1-2 \sin ^2 \theta\right]$
$=-\sin 2 \theta$

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