Question
$1 + \cos 2x + \cos 4x + \cos 6x = $
$ = (1 + \cos \,6x) + (\cos \,2x + \cos \,4x)$
$ = 2\,{\cos ^2}3x + 2\,\cos \,3x\,\cos x $
$= 2\,\cos \,3x\,(\cos \,3x + \cos \,x)$
$ = 4\,\cos x\,\cos \,2x\,\cos \,3x$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.