MCQ
${(1 + i)^{10}}$, where ${i^2} = - 1,$ is equal to
- ✓$32\ i$
- B$64 + i$
- C$24\ i -32$
- DNone of these
✓
Answer
Correct option: A.
$32\ i$
a
(a) ${(1 + i)^{10}} = {[{(1 + i)^2}]^5} = {(2i)^5} = 32\,i$.
(a) ${(1 + i)^{10}} = {[{(1 + i)^2}]^5} = {(2i)^5} = 32\,i$.
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