MCQ
$1$ mol of $C{H_4}$contains
- A$6.02 \times {10^{23}}$atoms of $H$
- ✓$4 \,g$ atom of Hydrogen
- C$1.81 \times {10^{23}}$molecules of $C{H_4}$
- D$3.0 \,g$ of carbon
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Statement-$I$: Since fluorine is more electronegative than nitrogen, the net dipole moment of $\mathrm{NF}_3$ is greater than $\mathrm{NH}_3$.
Statement-$II$: In $\mathrm{NH}_3$, the orbital dipole due to lone pair and the dipole moment of $\mathrm{NH}$ bonds are in opposite direction, but in $\mathrm{NF}_3$ the orbital dipole due to lone pair and dipole moments of $N-F$ bonds are in same direction. In the light of the above statements. Choose the most appropriate from the options given below.