Question
$\frac{{1 - {{\tan }^2}45^\circ }}{{1 + {{\tan }^2}45^\circ }} = $
✓
Answer
Given: $\frac{{1 - {{\tan }^2}45^\circ }}{{1 + {{\tan }^2}45^\circ }}$
= $\frac{{1 - {{\left( 1 \right)}^2}}}{{1 + {{\left( 1 \right)}^2}}} = \frac{{1 - 1}}{{1 + 1}}$= 0/2
= $\frac{{1 - {{\left( 1 \right)}^2}}}{{1 + {{\left( 1 \right)}^2}}} = \frac{{1 - 1}}{{1 + 1}}$= 0/2
= 0
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