Question
$1 - (x - 2) - [(x - 3) - (x - 1)] = 0$

Answer

Given, $1 - (x - 2) - [(x - 3) - (x - 1)] = 01 - x + 2 - [x - 3 + x + 1] = 0$
$3 - x - [-2] = 0$
$3 - x + 2 = 0$
$-x + 5 = 0$
$-x = -5$
$\frac{-\text{x}}{-1}=\frac{-5}{-1}$x = 5

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