Question
$10^{-2}=\frac{1}{100}$
✓
Answer
True.Solution:
Using law of exponents, $\text{a}^{-\text{m}}=\frac{1}{\text{}\text{a}^\text{m}}$ [$\because$ a is non-zero integer] $\therefore$ $10^{-2}=\frac{1}{10^2}$ $[\because10^2=10\times10]$ $=\frac{1}{10\times10}=\frac{1}{100}$
Using law of exponents, $\text{a}^{-\text{m}}=\frac{1}{\text{}\text{a}^\text{m}}$ [$\because$ a is non-zero integer] $\therefore$ $10^{-2}=\frac{1}{10^2}$ $[\because10^2=10\times10]$ $=\frac{1}{10\times10}=\frac{1}{100}$
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