Question
100 students appeared for two examination, 60 passed the first, 50 passed the second and 30 passed both. Find the probability that a student selected at random has passed at least one examination.

Answer

$\text{n}(\text{S})=100$ Let A be the event that students passed in first examination $\therefore\text{p}(\text{A})=\frac{60}{100}$ [60 students were passed in first exam] Let B be the event that students passed in second examination $\therefore\text{p}(\text{B})=\frac{50}{100}$ [50 students were passed in second exam] $\text{P}(\text{A}\cap\text{B})=\frac{30}{100}$ [$\because$ 30 students passed in both exam] $\therefore\text{P}(\text{A}\cup\text{B})=\text{p}(\text{A})+\text{p}(\text{B})-\text{P}(\text{A}\cap\text{B})$ $=\frac{60}{100}+\frac{50}{100}-\frac{20}{100}=\frac{8}{100}$ $=\frac{4}{5}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free