MCQ
$100\,\,ml$ of $0.2\,\,M\,\,{H_2}S{O_4}$ is added to $100\,\,ml$ of $0.2\,\,M\,\,NaOH.$ The resulting solution will be
- ✓Acidic
- BBasic
- CNeutral
- DSlightly basic
M.eq. of . $2\,M$ $NaOH$$ = \frac{{0.2}}{{1000}} \times 100 = 0.02\, m/l$
left $[{H^ + }] = 0.04 -0 .02 = 0.02$.
Total volume $ = 200 = \frac{{.02}}{{200}} = .0001 = {10^{ - 4}}\,M$
$pH = 4$.
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