MCQ
$110$ triangles can be formed by joning $10$ points as vertices in which $n$ points are collinear. Then the value of $n$ is
- ✓$5$
- B$6$
- C$3$
- D$4$
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$ +60(1+x)^{60}, x \neq 0 \text {, and }(60)^2 S(60)=a(b)^b+b$ where $a, b N$, then $(a+b)$ equal to...............