MCQ
$\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}=$
- A$-\frac{1}{3}$
- B$-\frac{1}{3}$
- ✓$-\frac{1}{12}$
- D$\frac{1}{12}$
Given that
we have to find the value of given expression
$\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}$
$=\frac{1}{\frac{1+3}{3}}-\frac{1}{\frac{1+2}{2}}$
$=\frac{3}{4}-\frac{2}{3} $
$=\frac{3\times3-2\times4}{12}$
$=\frac{1}{12}$
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