MCQ
$1.24\, gm \,P $ is present in $2.2\, gm$
- ✓${P_4}{S_3}$
- B${P_2}{S_2}$
- C$P{S_2}$
- D${P_2}{S_4}$
✓
Answer
Correct option: A.
${P_4}{S_3}$
a
(a) Choice $(a)$ is ${P_4}{S_3}$ $\frac{{31 \times 4}}{{(124)}}\,gm $ $P$ is present in $220\,gm$ ${P_4}{S_3}$
(a) Choice $(a)$ is ${P_4}{S_3}$ $\frac{{31 \times 4}}{{(124)}}\,gm $ $P$ is present in $220\,gm$ ${P_4}{S_3}$
$\therefore $ $1.24\,gm$ $P$ is present in = $\frac{{220}}{{124}} \times 1.24 = 2.2\,gm$
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