Question
$13 (\text{y}-4) -3 (\text{y}-9)-5(\text{y}+4)=0$

Answer

$13 (\text{y}-4) -3 (\text{y}-9)-5(\text{y}+4)=0$
$\Rightarrow13\text{y}-52-3\text{y+27}-5\text{y}-20=0$
$\Rightarrow13\text{y}-3\text{y}-5\text{y}-52+27-20=0$
$\Rightarrow13\text{y}-8\text{y}-72+27=0$
$\Rightarrow5\text{y - 45 = 0}$
Dividing by $5$, $\text{y}=9$
Verification:
$\text{L.H.S.}=13(\text{y} - 4)-3(\text{y} - 9) - 5 (\text{y}+4)$
$=13(9-4)-3(9-9)-5(9+4)$
$=13\times5-3\times0-5\times13$
$=65-0-65$
$=0$
$=\text{R.H.S.}$

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