^ 14 C_4 + _ j = 1 ^4 ^ 18 - j C_3 is equal to - Vidyadip

MCQ

$^{14}{C_4} + \sum\limits_{j = 1}^4 {^{18 - j}{C_3}} $ is equal to

A
$^{18}{C_3}$
✓
$^{18}{C_4}$
C
$^{14}{C_7}$
D
None of these

✓

Answer

Correct option: B.

$^{18}{C_4}$

b
(b) $^{14}{C_4}{ + ^{14}}{C_3}{ + ^{15}}{C_3}{ + ^{16}}{C_3}{ + ^{17}}{C_3}{ = ^{18}}{C_4}$.

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