We have, $\frac{16}{36}=\frac{?}{63}=\frac{36}{?}=\frac{?}{117}$
For first $2$ ratios, $\frac{16}{36}=\frac{4\times4}{9\times4}=\frac{4\times7}{9\times7}=\frac{28}{63}$
Hence, missing number $= 28$ For middle $2$ ratios,
$\frac{28}{63}=\frac{36}{?}$
$\frac{28}{63}=\frac{4\times7}{9\times7}=\frac{4\times9}{9\times9}=\frac{36}{81}$
Hence, missing number = 81 For last 2 ratios, $\frac{36}{81}=\frac{?}{117}$
$\frac{36}{81}=\frac{4\times9}{9\times9}=\frac{4\times13}{9\times13}=\frac{52}{117}$
Hence, missing number $= 52$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.