MCQ
$1\,eV$ is
- ASame as one joule
- ✓$1.6 \times {10^{ - 19}}J$
- C$1V$
- D$1.6 \times {10^{ - 19}}C$
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$\frac{\text{C}_\text{P}}{\text{C}_\text{V}}$
$\text{C}_\text{P}\text{C}_\text{V}$
$\text{C}_\text{P}-\text{C}_\text{V}$
$\text{C}_\text{P}+\text{C}_\text{V}$

$\frac{{dv}}{{dt}} = - 2.5\sqrt v$
where $v$ is the instantaneous speed. The time taken by the object, to come to rest, would be ........$s$