Question
1g chlorine
✓
Answer
Given: Mass of Chlorine $\left( Cl _2\right) m =7.1 g$.
To find: Number of molecules in 7.1 g of chlorine.
Solution: Atomic mass of (Cl) $=35.5$
$\therefore$ Molecular mass of chlorine $\left( Cl _2\right) M =35.5 \times 2=71$
According to the formula, Number of moles in the given $Cl _2( n )$
$\therefore 1 mol$ of $Cl _2$ contains $6.022 \times 10^{23}$ molecules.
$\therefore 0.1 mol$ of $Cl _2$ contains $0.1 \times 6.022 \times 10^{23}$ molecules.
$=0.6022 \times 10^{23} \text { molecules, }$
that is 7.1 g of $Cl _2$ contains $0.6022 \times 10^{23}$ molecules of $Cl _2$.
7.1 g of $Cl _2$ contains $0.6022 \times 10^{23}$ molecules of chlorine.
To find: Number of molecules in 7.1 g of chlorine.
Solution: Atomic mass of (Cl) $=35.5$
$\therefore$ Molecular mass of chlorine $\left( Cl _2\right) M =35.5 \times 2=71$
According to the formula, Number of moles in the given $Cl _2( n )$
$\therefore 1 mol$ of $Cl _2$ contains $6.022 \times 10^{23}$ molecules.
$\therefore 0.1 mol$ of $Cl _2$ contains $0.1 \times 6.022 \times 10^{23}$ molecules.
$=0.6022 \times 10^{23} \text { molecules, }$
that is 7.1 g of $Cl _2$ contains $0.6022 \times 10^{23}$ molecules of $Cl _2$.
7.1 g of $Cl _2$ contains $0.6022 \times 10^{23}$ molecules of chlorine.
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