(1+i)^ 10 , where i^2=-1, is equal to - Vidyadip

MCQ

$(1+i)^{10}$, where $i^2=-1$, is equal to

✓
32 i
B
$64+i$
C
$24 i-32$
D
24 i

✓

Answer

Correct option: A.

32 i

(A)
$(1+ i )^{10}=\left[(1+ i )^2\right]^5=\left(1+ i ^2+2 i \right)^5=(2 i )^5=32 i$

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