MCQ
$1−$phenyl$−2−$chloropropane on treating with $\text{alc. KOH}$ gives mainly:
- ✓$1-$phenylpropene
- B$2-$phenylpropene
- C$1-$phenylpropane$-2-ol$
- D$1-$phenylpropan$-1-ol$
✓
Answer
Correct option: A.
$1-$phenylpropene
$1−$phenyl$−2−$chloropropane on treating with $\text{alc. KOH}$ gives mainly $1−$phenylpropene. This is dehydrochlorination reaction.
The double bond in the product is in conjugation with benzene ring$.1−$phenyl$−2−$chloropropane.
The double bond in the product is in conjugation with benzene ring$.1−$phenyl$−2−$chloropropane.
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