MCQ
$(2^\circ + 4^{-1}) \times 2^2$is equal to.
  • A
    $2$
  • B
    $3$
  • C
    $4$
  • $5$

Answer

Correct option: D.
$5$
D.  $5$
Solution:
$(2^\circ+4^{-1})\times2^2$
$=\big(1+\frac{1}{4}\big)\times4$
$=\frac{5}{4}\times4 = 5$

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