MCQ
$2 \sin 22 \frac{1}{2}^{\circ} \cos 22 \frac{1}{2}^{\circ}=?$
  • A
    $\sqrt{2}$
  • B
    $\frac{1}{\sqrt{2}}$
  • C
    $\frac{1}{2}$
  • D
    1

Answer

(b) $\frac{1}{\sqrt{2}}$]
Explanation: Using $2 \sin A \cos A =\sin 2 A$, we get
$2 \sin 22 \frac{1}{2}^{\circ} \cos 22 \frac{1}{2}^{\circ}=\sin \left(2 \times \frac{45}{2}\right)^{\circ}=\sin 45^{\circ}=\frac{1}{\sqrt{2}}$

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