2 SO_ 2 (~g)+O_ 2 (~g) 2 SO_ 3 (~g) In an equilibrium mixture, th… - Vidyadip

MCQ

$2 \mathrm{SO}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{SO}_{3}(\mathrm{~g})$

In an equilibrium mixture, the partial pressures are

$P_{S O_{3}}=43\,\mathrm{kPa} ; \quad P_{O_{2}}=530 \,\mathrm{~Pa}$ and

$\mathrm{P}_{\mathrm{SO}_{2}}=45\, \mathrm{kPa}$ The equilibrium constant $\mathrm{K}_{\mathrm{p}}=......\times 10^{-2} .$ (Nearest integer)

A
$498$
B
$123$
C
$745$
✓
$172$

✓

Answer

Correct option: D.

$172$

d
$2 \mathrm{SO}_{2(9)}+\mathrm{O}_{2(\mathrm{~g})}=2 \mathrm{SO}_{3(9)}$

$\mathrm{K}_{\mathrm{p}}=\frac{\left(\mathrm{pSO}_{3(9)}\right)^{2}}{\mathrm{pSO}_{2(\mathrm{~g})}} \times \mathrm{pO}_{2(\mathrm{~g})}$

$=\frac{43 \times 43}{45 \times 45} \times 530\, \mathrm{~Pa}^{-1}=172.28 \times 10^{-5} \,\mathrm{~Pa}^{-1}$

$=174.498 \,\mathrm{~atm}^{-1}$

$=17449.8 \times 10^{-2}\, \mathrm{~atm}^{-1}$

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