Question
$2 x^2-7 x+6=0$ check whether (i) $x=\frac{3}{2}$,
✓
Answer
Put $x=\frac{3}{2}$ in the polynomial $2 x^2-7 x+6$
$2 x^2-7 x+6=2\left(\frac{3}{2}\right)^2-7\left(\frac{3}{2}\right)+6$
$32$
$=2 \times \frac{9}{4}-\frac{21}{2}+6$
$=\frac{9}{2}-\frac{21}{2}+\frac{12}{2}=0 $
$\therefore x=\frac{3}{2}$ is a solution of the equation.
$2 x^2-7 x+6=2\left(\frac{3}{2}\right)^2-7\left(\frac{3}{2}\right)+6$
$32$
$=2 \times \frac{9}{4}-\frac{21}{2}+6$
$=\frac{9}{2}-\frac{21}{2}+\frac{12}{2}=0 $
$\therefore x=\frac{3}{2}$ is a solution of the equation.
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