MCQ
$20\,ml$ of $HCl$ solution requires $19.85\,ml$ of $0.01\,M\,\,NaOH$ solution for complete neutralization. The molarity of $HCl$ solution is
- ✓$0.0099$
- B$0.099$
- C$0.99$
- D$9.9$
✓
Answer
Correct option: A.
$0.0099$
a
(a) ${M_1}{V_1} = {M_2}{V_2}$
(a) ${M_1}{V_1} = {M_2}{V_2}$
$0.01 \times 19.85 = {M_2} \times 20$
${M_2} = 0.009925$; $M = 0.0099$.
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