MCQ
$20\,ml$ of $HCl$ solution requires $19.85\,ml$ of $0.01\,M\,\,NaOH$ solution for complete neutralization. The molarity of $HCl$ solution is
- ✓$0.0099$
- B$0.099$
- C$0.99$
- D$9.9$
✓
Answer
Correct option: A.
$0.0099$
a
(a) ${M_1}{V_1} = {M_2}{V_2}$
(a) ${M_1}{V_1} = {M_2}{V_2}$
$0.01 \times 19.85 = {M_2} \times 20$
${M_2} = 0.009925$; $M = 0.0099$.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The major product of the following reaction is $C{H_3}CH = CHC{O_2}C{H_3}\,\xrightarrow{{LiAl{H_4}}}$
→The catalytic promoter used in Haber's process is:
What will be the degree of dissociation of $\ce{0.1M Mg(NO_3)_2}$ solution if van’t Hoff factor is $2.74?$
→$[Co(en)_3]^{3+}$ ion is expected to show
→For the octahedral complexes of $Fe ^{3+}$ in $SCN$ (thiocyanato- $S$ ) and in $CN$ ligand environments, the difference between the spin-only magnetic moments in Bohr magnetons (When approximated to the nearest integer) is
→[Atomic number of $Fe =26$ ]
Propionic acid with $Br_2/P$ yields a dibromo product. Its structure would be
→Among the sugar mentioned below, name the sweetest one :
Identify the reagents used for the following conversion
Hydrogen occupies the $......$ holes, while carbon and nitrogen occupy $......$ holes:
→In nucleuphilic substitution reaction, order of halogens as incoming (attacking) nucleophile is:
$I^-> Br^ - > Cl^-$
The order of halogens as departing nucleophile should be
→$I^-> Br^ - > Cl^-$
The order of halogens as departing nucleophile should be