MCQ
$2.0\,molar$ solution is obtained , when $ 0.5\,mole$ solute is dissolved in
- A$250\,ml$ solvent
- B$250\,g$ solvent
- ✓$250\,ml$ solution
- D$1000\,ml$ solvent
Molarity $ = \frac{{{\rm{Number\,of \, moles\, of \, solute}}}}{{{\rm{Volume\,of\, solution\, in }}litre}}$
$\therefore 2.0 = \frac{{0.5}}{{{\rm{Volume\, of\, solution\, in}}\,\,litre}}$
Volume of solution in litre $ = \frac{{0.5}}{{2.0}} = 0.250\,litre = 250\,ml.$
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$2{N_2}{O_5}\, \to \,4N{O_2}\, + \,{O_2}$
the rate of reaction is
$C{u_{\left( s \right)}} + 2Ag_{\left( {aq} \right)}^ + \to Cu_{\left( {aq} \right)}^{2 + } + 2A{g_{\left( s \right)}}$