MCQ
$23\, g$ of $Na$ will react with methyl alcohol to give
- AOne mole of oxygen
- BOne mole of ${H_2}$
- ✓$\frac{1}{2}$ mole of ${H_2}$
- DNone of these
✓
Answer
Correct option: C.
$\frac{1}{2}$ mole of ${H_2}$
c
(c) $\mathop {C{H_3}OH + Na \to C{H_3}ONa}\limits_{1\,mole\,\,\,\,\,\,\,\,\,\,\,\,\mathop {1\,mole}\limits_{(23\,gms)} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} + \mathop {\frac{1}{2}{H_2}}\limits_{\,1/2\,mole} $
(c) $\mathop {C{H_3}OH + Na \to C{H_3}ONa}\limits_{1\,mole\,\,\,\,\,\,\,\,\,\,\,\,\mathop {1\,mole}\limits_{(23\,gms)} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} + \mathop {\frac{1}{2}{H_2}}\limits_{\,1/2\,mole} $
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