MCQ
$23\, g$ of sodium will react with methyl alcohol to give
- Aone mole of oxygen
- B$22.4\, dm^3$ of hydrogen gas at $NTP$
- C$1\, mole$ of $H_2$
- ✓$1 1.2 \,L$ of hydrogen gas at $NTP$

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$[{R_H} = 1 \times {10^5}\,c{m^{ - 1}},\,h\, = 6.6\, \times {10^{ - 34}}\,Js\,\,c = 3\, \times \,{10^8}\,m{s^{ - 1}}]$
