MCQ
$23\, g$ of sodium will react with methyl alcohol to give
- Aone mole of oxygen
- B$22.4\, dm^3$ of hydrogen gas at $NTP$
- C$1\, mole$ of $H_2$
- ✓$1 1.2 \,L$ of hydrogen gas at $NTP$

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$HCl_{ ( g )}$ are $-105,-242,-394$ and $-92\,kJ\,mol ^{-1}$
respectively. The magnitude of enthalpy of the reaction given below is $......kJ\,mol ^{-1}$
(nearest integer) $CCl _{4( g )}+2 H _2 O_{( g )} \rightarrow CO _{2( g )}+4 HCl_{( g )}$