MCQ
$23\, g$ of sodium will react with methyl alcohol to give
- Aone mole of oxygen
- B$22.4\, dm^3$ of hydrogen gas at $NTP$
- C$1\, mole$ of $H_2$
- ✓$1 1.2 \,L$ of hydrogen gas at $NTP$

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$X$ and $Y$ should be

Product $(A)$ of above reaction is
$(a)\,N{H_4}N{O_2}\xrightarrow{\Delta }{N_2} + {H_2}O$
$(b)\,N{H_4}N{O_3}\xrightarrow{\Delta }{N_2}O + {H_2}O$
$(c)\,N{a_2}C{O_3}\xrightarrow{\Delta }N{a_2}O + C{O_2}$
$(d)\,N{H_4}Cl\xrightarrow{\Delta }N{H_3} + HCl$