25 5 x 5 x d x= - Vidyadip

MCQ

$25 \int \sec 5 x \tan 5 x d x=$

A
$25 \sec 5 x+k$
✓
$5 \sec 5 x+k$
C
$25 \tan 5 x+k$
D
$\sec 5 x+k$

✓

Answer

Correct option: B.

$5 \sec 5 x+k$

B

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ [1M]" from समाकलन→समाकलन — all question types→गणित कक्षा 12 साइन्स question papers→Bihar Board कक्षा 12 साइन्स question papers→Bihar Board question paper generator→

Similar questions

यदि $y=\log |x|, x \neq 0$ तो $\frac{d y}{d x}=$

$\int_0^{\pi / 4}(\sqrt{\tan x}+\sqrt{\cot x}) d x=$

$\left|\begin{array}{lll}1 & 1 & -2 \\ 2 & 1 & -3 \\ 5 & 4 & -9\end{array}\right|=$

समीकरणों $2 x-3 y+6 z=4,5 x+7 y-14 z=$$1$ व $3 x+2 y-4 z=0$ के होते हैं

$\frac{d}{d x}(\sin x)=$

यदि $\cot ^{-1} \sqrt{\cos \theta}-\tan ^{-1} \sqrt{\cos \theta}=x$ तब $\sin x=$ :

यदि $y=\sqrt{\sin x+\sqrt{\sin x+\sqrt{\sin x+\ldots \infty}}}$ तो $\frac{d y}{d x}=$

$\vec{k} \cdot \vec{k}=$

व्यंजक $2 \sec ^{-1} 2+\sin ^{-1}\left(\frac{1}{2}\right)$ का मान है

$\sin ^{-1}\left(\frac{1}{\sqrt{2}}\right)=?$