Question
$(27)^{-\frac{2}{3}}$ is Equal to:
✓
Answer
$27$ can be written as $(3)^3$
So$, (27)^{-\frac{2}{3}}=\{(3)^3\}^{-\frac{2}{3}}$
$=\frac{1}{(3)^2}=\frac{1}{9}$
So$, (27)^{-\frac{2}{3}}=\{(3)^3\}^{-\frac{2}{3}}$
$=\frac{1}{(3)^2}=\frac{1}{9}$
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