MCQ
$(27)^{-\frac{2}{3}}$ is Equal to:
- A3
- B$\frac{1}{9}$
- C9
- DNone of these.
✓
Answer
- $\frac{1}{9}$
Solution:
27 can be written as (3)3
So, $(27)^{-\frac{2}{3}}=\{(3)^3\}^{-\frac{2}{3}}$
$=\frac{1}{(3)^2}=\frac{1}{9}$
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