MCQ
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- A

- ✓

- C

- D







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What is $Y$ in the above reaction?

$C{H_3} - C{H_2} - Br\xrightarrow{{{\text{alc}}{\text{.KCN}}}}$ $C{H_3}C{H_2}CN$$\xrightarrow{{{\text{HOH}}}}X$