
- A

- B

- ✓

- D







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Statement $I$: The boiling point of hydrides of Group $16$ elements follow the order
$\mathrm{H}_2 \mathrm{O}>\mathrm{H}_2 \mathrm{Te}>\mathrm{H}_2 \mathrm{Se}>\mathrm{H}_2 \mathrm{~S}$.
Statement $II$: On the basis of molecular mass, $\mathrm{H}_2 \mathrm{O}$ is expected to have lower boiling point than the othe members of the group but due to the presence of extensive $\mathrm{H}$-bonding in $\mathrm{H}_2 \mathrm{O}$, it has higher boiling point.
In the light of the above statements, choose the correct answer from the options given below:
$X + {H_2}S{O_4} \to Y + BaS{O_4}$
$Y\xrightarrow[{\Delta \, > \,365\,K}]{\Delta }Z + {H_2}O + {O_2}$
$Y$ and $Z$ are respectively


| $I$ | $II$ | |
| $[Cr(H_2O)_6]^{+2}$ | $[Cr(H_2O)_6]^{+3}$ | $(a)$ |
| $[Fe(H_2O)_6]^{+3}$ | $[Fe(CN)_6]^{-3}$ | $(b)$ |
| $[Fe(CN)_6]^{+3}$ | $[Ru(CN)_6]^{-3}$ | $(c)$ |
| $[NiF_6]^{-4}$ | $[NiF_6]^{-2}$ | $(d)$ |