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Introduction of Trigonometry — Maths STD 10 — Question

CBSE BoardEnglish MediumSTD 10MathsIntroduction of Trigonometry1 Mark
Question
$\frac{2\cos67^\circ}{\sin23^\circ}-\frac{\tan40^\circ}{\cot50^\circ}-\cos0^\circ=$ __________.
✓

Answer

$\frac{2\cos67^\circ}{\sin23^\circ}-\frac{\tan40^\circ}{\cot50^\circ}-\cos0^\circ=$ 0.
Solution:
$=\frac{2\cos67^\circ}{\sin23^\circ}-\frac{\tan40^\circ}{\cot50^\circ}-\cos0^\circ$
$=\frac{2\sin(90-67)}{\sin23}-\frac{\cot(90-40)}{\cot50}-1$
$=2-1-1$
$=2-2=0.$

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