MCQ
$2\pi\text{cm}^2$ The surface area of a cube whose volume is $64\ cm^3$ is:
- A$108\ cm^2$
- ✓$96\ cm^2$
- C$64\ cm^2$
- D$72\ cm^2$
$\text { Given: Volume of cube }=64 \mathrm{~cm}^3$
$\Rightarrow a^3=64$
$\Rightarrow a^3=(4)^3$
$\Rightarrow a=4 \mathrm{~cm}$
$\therefore \text { Surface Area of cube }=6 a^2=6(4)^2=96 \text { sq. } \mathrm{cm}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

