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STD 12 - 2. inverse trigonometric function — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 - 2. inverse trigonometric function4 Marks
MCQ
$2{\sin ^{ - 1}}\frac{3}{5} + {\cos ^{ - 1}}\frac{{24}}{{25}} = $
  • ✓
    $\frac{\pi }{2}$
  • B
    $\frac{{2\pi }}{3}$
  • C
    $\frac{{5\pi }}{3}$
  • D
    None of these
✓

Answer

Correct option: A.
$\frac{\pi }{2}$
a
(a) $2\,{\sin ^{ - 1}}\frac{3}{5} + {\cos ^{ - 1}}\frac{{24}}{{25}} = {\sin ^{ - 1}}2 \times \frac{3}{5}\sqrt {1 - \frac{9}{{25}}} + {\cos ^{ - 1}}\frac{{24}}{{25}}$

$ = {\sin ^{ - 1}}\frac{{24}}{{25}} + {\cos ^{ - 1}}\frac{{24}}{{25}} = \frac{\pi }{2}$.

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