Question
$2\tan^{-1}(\cos\text{x})=\tan^{-1}(2\text{cosec x})$
- $0$
- $\frac{\pi}{3}$
- $\frac{\pi}{4}$
- $\frac{\pi}{2}$
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$\frac{\pi^2}{4}$
$\frac{\pi^2}{2}$
$\frac{3\pi^2}{2}$
$\frac{\pi^2}{2}$