MCQ
$\frac{2^{\text{n}+4}-2(2^\text{n}}{2(2^{\text{n}+3})}+2^{-3}$ is equal to
- A$2^{\text{n}+1}$
- B$-2^{\text{n}+1}+\frac{1}{8}$
- C$\frac{9}{8}-2^\text{n}$
- ✓$1$
$\frac{2^{\text{n}+4}-2(2^\text{n}}{2(2^{\text{n}+3})}+2^{-3}$
$=\frac{2^{\text{n}+4}-(2^{\text{n}+4})}{(2^{\text{n}4})}+2^{-3}$
$=1-2^{-3}+2^{-3}=1$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.