Question
$\frac{2\text{y}-3}{4}-\frac{3\text{y}-5}{2}=\text{y}+\frac{3}{4}$
✓
Answer
Given, $\frac{2\text{y}-3}{4}-\frac{3\text{y}-5}{2}=\text{y}+\frac{3}{4}$ $\frac{2\text{y}-3-2(3\text{y}-5)}{4}=\frac{4\text{y}+3}{4}$$2y - 3 - 6y + 10 = 4y + 3$
$-4y + 7 = 4y + 3$
$-4y - 4y = 3 - 7$
$-8y = -4$
$\frac{-8\text{y}}{-8}=\frac{-4}{-8}$ $\text{y}=\frac{1}{2}$
$-4y + 7 = 4y + 3$
$-4y - 4y = 3 - 7$
$-8y = -4$
$\frac{-8\text{y}}{-8}=\frac{-4}{-8}$ $\text{y}=\frac{1}{2}$
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