MCQ
$3 \times 0.3 \times 0.03 \times 0.003 \times 30 =$
- A$0.0000243$
- B$0.000243$
- ✓$0.00243$
- D$0.0243$
$=3 \times 0.3 \times 0.03 \times 0.003 \times 30$
$=3\times\frac{3}{10}\times\frac{3}{100}\times\frac{3}{1000}\times3\times10$
$=\frac{3\times3\times3\times3\times3}{100\times1000}$
$=\frac{243}{100000}$
$=0.00243 ($Decimal point is shifted to left by $5$ places$)$
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