Question
$3 \frac{1}{3}-1 \frac{1}{4}$
✓
Answer
$\begin{aligned} & \text {} 3 \frac{1}{3}-1 \frac{1}{4} \\ & 3 \frac{1}{3}-1 \frac{1}{4}=\frac{3 \times 3+1}{3}-\frac{1 \times 4+1}{4} \\ & =\frac{9+1}{3}-\frac{4+1}{4} \\ & =\frac{10}{3}-\frac{5}{4} \\ & =\frac{10 \times 4}{3 \times 4}-\frac{5 \times 3}{4 \times 3} \\ & =\frac{40}{12}-\frac{15}{12} \\ & =\frac{40-15}{12}=\frac{25}{12} \\ & \therefore \quad 3 \frac{1}{3}-1 \frac{1}{4}=2 \frac{1}{12} \\ & \end{aligned}$
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