MCQ
$3^{-2}\times 3^{-5}$ is equal to:
- ✓$3^{-7}$
- B$3^{-3}$
- C$3^{-10}$
- D$3^{7}$
✓
Answer
Correct option: A.
$3^{-7}$
A. $3^{-7}$
Solution:
$3^{-2}\times3^{-5}$
$\frac{1}{3^2}\times\frac{1}{3^5}$
$=\big(\frac{1}{3^{2+5}}\big)$
$=\big(\frac{1}{3^{7}}\big)$
$=3^{-7}$
Solution:
$3^{-2}\times3^{-5}$
$\frac{1}{3^2}\times\frac{1}{3^5}$
$=\big(\frac{1}{3^{2+5}}\big)$
$=\big(\frac{1}{3^{7}}\big)$
$=3^{-7}$
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