MCQ
$3^{-2} \times 3^{-5}$ is equal to:
  • A
    $3^{-3}$
  • B
    $3^{-10}$​​​​​​​
  • C
    $3^{7}$​​​​​​​
  • $3^{-7}$​​​​​​​

Answer

Correct option: D.
$3^{-7}$​​​​​​​
D. $3^{-7}$​​​​​​​
Solution:
$3^{-2} × 3^{-5} = \frac{1}{3^2}\times \frac{1}{3^5}$
$=\frac{1}{3^{2+5}}$
$=\frac{1}{3^7}$
$=3^{-7}$

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